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x^2+3=-x^2+1
We move all terms to the left:
x^2+3-(-x^2+1)=0
We get rid of parentheses
x^2+x^2-1+3=0
We add all the numbers together, and all the variables
2x^2+2=0
a = 2; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·2·2
Δ = -16
Delta is less than zero, so there is no solution for the equation
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